Elementary Algebra SkillSolving Quadratic equations : Completing the SquareSolve each equation by Completing the ) x 2 + 2 x 24 = 02) p 2 + 12 p 54 = 03) x 2 8 x + 15 = 04) r 2 + 18 r + 56 = 05) m 2 6 m 55 = 06) m 2 4 m 91 = 07) m 2 + 16 m 32 = 78) r 2 8 r = 89) n 2 = 14 n 3710) n 2 2 n = 1511) x 2 + 15 x + 15 = 2 + x 12) 3 n 2 + 4 n 59 = 4 n 213) 5 n 2 20 n + 6 = 014) 3 a 2 6 a 34 = 015) 3 x 2 x 3 = 016) 2 v 2 + 5 v 7 = 017)
Elementary Algebra Skill Solving Quadratic Equations: Completing the Square Solve each equation by completing the square. 1) x2 + 2x − 24 = 0 2) p2 + 12p − 54 = 0 3) x2 − 8x + 15 = 0 4) r2 + 18r + 56 = 0 5) m2 − 6m − 55 = 0 6) m2 − 4m − 91 = 0 7) m2 + 16m − 32 = −7 8) r2 − 8r = −8 9) n2 = −14n − 37 10) n2 − 2n = 15 11) x2 + 15x + 15 = 2 + x 12) −3n2 + 4n − 59 ...
1 Elementary Algebra SkillSolving Quadratic equations : Completing the SquareSolve each equation by Completing the ) x 2 + 2 x 24 = 02) p 2 + 12 p 54 = 03) x 2 8 x + 15 = 04) r 2 + 18 r + 56 = 05) m 2 6 m 55 = 06) m 2 4 m 91 = 07) m 2 + 16 m 32 = 78) r 2 8 r = 89) n 2 = 14 n 3710) n 2 2 n = 1511) x 2 + 15 x + 15 = 2 + x 12) 3 n 2 + 4 n 59 = 4 n 213) 5 n 2 20 n + 6 = 014) 3 a 2 6 a
34 = 015) 3 x 2 x 3 = 016) 2 v 2 + 5 v 7 = 017) 2 4 n 2 + 11 n = 1518) 9 a 2 21 = 13 a 19) 3 m 2 10 m + 11 = 420) 3 m 2 16 m 2 = 7 Answers to Solving Quadratic equations : Completing the Square1) {4, 6}2) { 6 + 3 10, 6 3 10}3) {5, 3}4) { 4, 14}5) {11, 5}6) { 2 + 95, 2 95}7) { 8 + 89, 8 89}8) { 4 + 2 2, 4 2 2}9) { 7 + 2 3, 7 2 3}10) {5, 3}11) { 1, 13}12) { 2 + 3 7, 2 3 7}13) { 10 + 705, 10 705}14) { 3 + 1113, 3
1113}15) { 1 + 376, 1 376}16) {1, 3 12}17) {1, 3 34}18) { 13 + 5 3718, 13 5 3718}19) 3 {2 13, 1}20) {5, 13}Transcription of Solving Quadratic Equations: Completing the Square
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The University of Texas at El Paso
John P.
Algebra
4 months, 4 weeks ago
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Solve each equation by completing the square and applying the square root property. $2 r^{2}+12 r+16=0$
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we need to solve the following by completing the square. We're going to pull the two out of the first two terms. Move the 16 over. We're going to take the six divided by two and square it so that's plus nine but that nine is getting multiplied to the two, so we're really adding 18. So this is two times are plus three squared is equal to two. We divide both sides by two, so we get our plus three squared is equal to one. We take the square root of both sides and we get our plus three is equal to plus minus one. We move the three over, we get negative three plus minus one. So our solutions are r is equal to negative three plus one, so it's negative two. We all have our is equal to negative three minus one. R is equal to negative four. So our two solutions are negative for a negative two.
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Tags
Quadratic equation, Elementary algebra, 18r